Solve each triangle round to the nearest tenth calculator

Rounding To The Nearest Tenth

Rounded Number:

(to nearest tenth)

Solve each triangle round to the nearest tenth calculator

Rounding to the Nearest Tenth Calculator is a free online tool that displays the given number rounded to its nearest tenths place value. BYJU’S online rounding to the nearest tenth calculator tool performs the calculation faster, and it displays the rounded value in a fraction of seconds.

The procedure to use the rounding to the nearest tenth calculator is as follows:

Step 1: Enter the decimal number in the input field

Step 2: Now click the button “Solve” to get the rounded value

Step 3: Finally, the decimal number rounded to the nearest tenth place value will be displayed in the output field

What is Meant by Rounding to the Nearest Tenth?

In  Mathematics, the decimal number is the combination of the whole number and a fraction separated by a decimal point. From left to right, the place value of the digits is divided by 10. Thus, the decimal place value will help to determine the place values of tenths, hundredths, thousands. For example, the place value tenth is defined as 1/10 (one-tenth).

Consider a decimal number 12.345.

Here, the tenth place value is 3. 

The decimal number can be rounded by replacing the number with the approximation of the number. For example, the decimal number 5.8 rounded to the nearest integer is 6. Similarly, we can round the decimal number to its nearest tenths place value. The tenth place value is the first number which appears first after the decimal point. To round the decimal number to its nearest tenth, look at the hundredth number. If that number is greater than 5, add 1 to the tenth value. If it is less than 5, leave the tenth place value as it is, and remove all the numbers present after the tenth’s place.

For example,

4.624 rounded to the nearest tenth is 4.6. Because the hundredths place value “2” is less than 5. 

7.469 rounded to the nearest tenth is 7.5, as the hundredth’s place value “6” is greater than 5.

Disclaimer: This calculator development is in progress some of the inputs might not work, Sorry for the inconvenience.

Please enter two sides and a non-included angle

a =

b =

β =

°

The calculator solves the triangle given by two sides and a non-included angle between them (abbreviation SSA side-side-angle). The picture shows a typical case of solving a triangle when thee are given two sides a, b and one non-included angle (opposing angle) β. Uses quadratic equation (can be zero, one or two solutions), then Heron's formula and trigonometric functions to calculate the area and other properties of a given triangle.

Look also at our friend's collection of math problems and questions:

  • triangle
  • right triangle
  • Heron's formula
  • The Law of Sines
  • The Law of Cosines
  • Pythagorean theorem
  • triangle inequality
  • similarity of triangles
  • The right triangle altitude theorem

See more information about triangles or more details on solving triangles.

a=3 b=4 c=5 ... triangle calc by three sides a,b,c.
B=45 c=10 a=9 ... triangle calc by two sides a,c and included angle B.
A=25 C=80 b=22
A=35 C=26 a=10
a=3 C=90 c=5 ... how to enter right-angled triangle.
a=3 β=25 γ=45 ... triangle calc if we know the side and two angles.
a=3 β=25 T=12 ... triangle calc, if know side, angle, and area of a triangle.
T=2.5 c=2 b=4 ... find side a if know sides b, c, and area of triangle T.
ma=1 b=2.5 c=2 ... calculation of the triangle if we know one median and any two sides.
ma=1 mb=2.5 mc=2 ... triangle calc by three medians.
ha=220, hb=165 hc=132 ... triangle calc by three heights.
a=7 β=40 mc=5 ... triangle calc by one side, one angle, and one median.
a:b:c=2:3:4 T=2.5 ... a triangle where the known side ratio, and its area.
A:B:C=1:4:5 a=2 ... calculating triangle if we know the ratio of the internal angles and one side.

What do the symbols mean?

a, b, c ... sides BC, AC, AB
A, B, C or α, β, γ ... internal angles
ha, hb, hc ... heights
ma, mb, mc ... medians
T ... area
p ... perimeter
s ... semiperimeter

Please provide any 2 values below to solve the Pythagorean equation: a2 + b2 = c2.

   
Solve each triangle round to the nearest tenth calculator


Pythagorean Theorem

The Pythagorean Theorem, also known as Pythagoras' theorem, is a fundamental relation between the three sides of a right triangle. Given a right triangle, which is a triangle in which one of the angles is 90°, the Pythagorean theorem states that the area of the square formed by the longest side of the right triangle (the hypotenuse) is equal to the sum of the area of the squares formed by the other two sides of the right triangle:

Solve each triangle round to the nearest tenth calculator

In other words, given that the longest side c = the hypotenuse, and a and b = the other sides of the triangle:

a2 + b2 = c2

This is known as the Pythagorean equation, named after the ancient Greek thinker Pythagoras. This relationship is useful because if two sides of a right triangle are known, the Pythagorean theorem can be used to determine the length of the third side. Referencing the above diagram, if

a = 3 and b = 4

the length of c can be determined as:

c = √a2 + b2 = √32+42 = √25 = 5

It follows that the length of a and b can also be determined if the lengths of the other two sides are known using the following relationships:

a = √c2 - b2

b = √c2 - a2

The law of cosines is a generalization of the Pythagorean theorem that can be used to determine the length of any side of a triangle if the lengths and angles of the other two sides of the triangle are known. If the angle between the other sides is a right angle, the law of cosines reduces to the Pythagorean equation.

There are a multitude of proofs for the Pythagorean theorem, possibly even the greatest number of any mathematical theorem.

Algebraic proof:

Solve each triangle round to the nearest tenth calculator

In the figure above, there are two orientations of copies of right triangles used to form a smaller and larger square, labeled i and ii, that depict two algebraic proofs of the Pythagorean theorem.

In the first one, i, the four copies of the same triangle are arranged around a square with sides c. This results in the formation of a larger square with sides of length b + a, and area of (b + a)2. The sum of the area of these four triangles and the smaller square must equal the area of the larger square such that:

(b + a)2 = c2 + 4 = c2 + 2ab

which yields:

c2 = (b + a)2 - 2ab
= b2 + 2ab + a2 - 2ab
= a2 + b2

which is the Pythagorean equation.

In the second orientation shown in the figure, ii, the four copies of the same triangle are arranged such that they form an enclosed square with sides of length b - a, and area (b - a)2. The four triangles with area

also form a larger square with sides of length c. The area of the larger square must then equal the sum of the areas of the four triangles and the smaller square such that:

(b - a)2 + 2ab
= b2 - 2ab + a2 + 2ab
= a2 + b2

Since the larger square has sides c and area c2, the above can be rewritten as:

c2 = a2 + b2

which is again, the Pythagorean equation.

There are numerous other proofs ranging from algebraic and geometric proofs to proofs using differentials, but the above are two of the simplest versions.