#" "# #color(red)(y=f(x)=a(x-h)^2+k#, where #color(red)((h,k)# is the #color(blue)("Vertex"# Let us consider a quadratic equation in Vertex Form: #color(blue)(y=f(x)=(x-3)^2+8#, where #color(green)(a=1; h=3; k=8# Hence, #color(blue)("Vertex "= (3, 8)# To find the y-intercept, set #color(red)(x=0# #y=(0-3)^2+8# #y=9+8# #y= 17# Hence, the y-intercept: #color(blue)((0, 17)# We can use a table of values to draw the graph: Use the table with two columns #color(red)(x and y# to draw the graph as shown below: The Parent Graph of #color(red)(y=x^2# can also be seen for comparison, to better understand transformation. Also note that, Axis of Symmetry is #color(red)(x=h# #rArr x= 3# We can verify this from the graph below: Hope it helps.
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