EOC FORMULA SHEET WELCOME BACK! - HW: KEYTuesday, April
9 - HW: KEYWednesday, April 10 - HW: KEYThursday, April 11 ***#3 is wrong! you should subtract 2/52 because there are two red aces! so the final answer should be 7/13!!! BLANK COPY!- Venn Diagram Matching Game- - STUDY STUDY Friday, April 12 Monday, April 15 - Classwork: KEY- HW: KEYTuesday, April 16 - HW: KEYWednesday, April 17 - HW/quiz review: KEY - do not do #3 b & d on the backThursday, April 18 Friday, April 19 Wednesday, May 1 - STUDY FOR YOUR TEST ON FRIDAY, MAY 3RD!!! Thursday, May 2 Friday, May 3 - Extra Practice KEY
Let A and B be two events associated with a random experiment. Then, probability of the occurrence of A given that B has already occurred is called conditional probability and denoted by P(A/B) Example : A bag contains 5 black and 4 blue balls. Two balls are drawn from the bag one by one without replacement. What is the probability of drawing a blue ball in the second draw if a black ball is already drawn in the first draw? Let A be the event of drawing black ball in the first draw and B be the event of drawing a blue ball in the second draw. Then, P(B/A) = Probability of drawing a blue ball in the second draw given that a black ball is already drawn in the first draw. Total Balls = 5 + 4 = 9 Since a black ball is drawn already, |